A steel plate, connected to a fixed Channel using three

A steel plate, connected to a fixed Channel using three identical bolts A, B and C, carries a load of 6 kN as shown in the figure. Considering the effect of direct load and moment, the magnitude of resultant shear force (in kN) on bolt C is

P_p =	P	=	P	= 2 kN.
	n		3

r_A = r_C = 50, (P_S)_A = (P_S)_C
r_B = 0 ⇒ (P_S)_B = 0

(P_S)_C =	200	[r_C² + r_B² + r_A²] = P × e
	r_C

(P_S)_C × 2 × r_C = P × e

(P_S)_C =	6 × 250	= 15 KN
	2 × 50

Q_A = 180°, Q_C = 0°
Resultant shear force (R_C) = PP + (P_S) C.
R_C = 2 + 15 = 17 KN