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  1. A ball bearing operating at a load F has 8000 hours of life. The life of the bearing, in hours, when the load is doubled to 2F is
    1. 8000
    2. 6000
    3. 4000
    4. 1000
Correct Option: D

Life ∝
1
(Load)3

∴ New Life =
8000
= 1000 hours
(2)3



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