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A Journal bearing has a shaft diameter of 40 mm and a length of 40 mm. The shaft is rotating at 20 rad/s and the viscosity of the lubricant is 20 mPa.s. The clearance is 0.020 mm. The loss of torque due to the viscosity of the lubricant is approximately
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- 0.040 Nm
- 0.252 Nm
- 0.400 Nm
- 0.652 Nm
Correct Option: A
| τ = | = | = 400N/m2 | ||
| c | 0.02 × 10-3 |
Force = dA = 400 × 3.14 × .04 × .04
Torque = Force × .02 = .040 N-m
