Home » Thermodynamics » Thermodynamics Miscellaneous » Question
  1. A reversible cycle receives 40 kJ of heat from one heat source at a temperature of 127°C and 37 kJ from another heat source at 97°C. The heat rejected (in kJ) to the heat sink at 47°C is________
    1. 87
    2. 64
    3. 68
    4. 75
Correct Option: B


Q1
+
Q2
-
Q3
> 0
T1T2T3

40
+
37
-
Q3
= 0
127 + 27397 + 27347 + 273

Q3 = 64 kJ



Your comments will be displayed only after manual approval.