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A parabola x = y² with 0 ≤ x ≤ 1 is shown in the figure. The volume of the solid of rotation obtained by rotating the shaded area by 360° around the x-axis is
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- 2π
- π/2
- π/4
- π
Correct Option: B
Here, volume of solid of rotation by rotating shaded area by 360° around x-axis is,
V = 1∫0πy²dx
V = 1∫0 πx dx = | ² | = | |||
2 | 0 | 2 |