The solution to the differential equationd²u - kdu

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The solution to the differential equation d²u - k du = 0
dx² dx

is where k is constant, subjected to the boundary conditions u(0) = 0 and u(L) = U, is

1. u = U x
  L
2. u = U 1 - e^kx
  1 - e^kL
3. u = U 1 - e^-kx
  1 - e^-kL
4. u = U 1 + e^kx
  1 + e^kL

Correct Option: B

NA