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Four red balls, four green balls and four blue balls are put in a box. Three balls are pulled out of the box at random one after another without replacement. The probability that all the three balls are red is
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- 1/72
- 1/55
- 1/36
- 1/27
Correct Option: B
(4R, 4G, 4B)
P(RRR) (without replacement)
= | × | × | = | ||||
12C1 | 11C1 | 10C1 | 55 |