Torque exerted on a flywheel over a cycle is listed in

Home » Engineering Mathematics » Engineering Mathematics Miscellaneous » Question

Torque exerted on a flywheel over a cycle is listed in the table. Flywheel energy (in J per unit cycle) using Simpson's rule is Angle (degree)

1. 542
2. 993
3. 1444
4. 1986

Correct Option: B

Given: h = 60° – 0° = 60° = 60 × π/180 = 1.047
y₀ = 0, y₁ = 1066, y₂ = – 323, y₄ = 323, y₅ = – 355, y₆ = 0
By Simpson’s rule, flywheel energy
= h/3[(y₀ + y₆) + 4(y₁ + y₃ + y₅) + 2(y₂ + y₄)]
= 1.047/3 [(0 + 0) + 4(1066 + 0 - 355) + 2(- 323 + 323)
= 993 Nm rad
= 993 Joules/cycle