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A block mass 10 kg rests on a horizontal floor. The acceleration due to gravity is 9.81 m/s². The coefficient of static friction between the floor and the block is 0.2. A horizontal force of 10 N is applied on the block as shown in the figure. The magnitude of force of friction (in N) on the block is
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- 14N
- 11N
- 10N
- 9N
Correct Option: C
Here, μ = 0.2
g = 9.81 m/s²
M = 10 kg
(fs)max = μMg
= 0.2 × 10 × 9.81 = 19.62N
As, (Fs)max > Force applied
So, magnitude of force of friction on block is,
(Fs) = 10N