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A 1 kg mass of clay, moving with a velocity of 10 m/s, strikes a stationary wheel and sticks to it. The solid wheel has a mass of 20 kg and a radius of 1 m. Assuming that the wheel is set into pure rolling motion, the angular velocity of the wheel immediately after the impact is approximately
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- zero
- 1/3 rad/s
- √10/3rad/s
- 10/3 rad/s
Correct Option: B
Taking both clay & wheel as system
Li = Lf (about A) 
Li = mvr = 1 × 10 × 1 = 10
Lf = mvcm r + Iω
| = 20 × rω × r + | = 20ω + 10ω | |
| 2 |
Lf = 30ω
Li = Lf
10 = 30ω
ω = 1/3 rad/sec
