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The root of the function f(x) = x3 + x – 1 obtained after first iteration on application of Newton Raphson scheme using an initial guess of x0 = 1 is
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- 0.682
- 0.686
- 0.750
- 1.000
Correct Option: C
f (x) = x3 + x–1
f (1) = 1+1 – 1 = 1
f’(x) = 3x2 + 1
f’ (1) = 3+1=4
| x1 = x0 - | = 1 - | ||||
| f'(x0) | 4 |
= 1 – 0.25
x1 = 0.75
