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Square key of side d/4 each and length l is used to transmit torque T from the shaft of diameter d to the hub of a pulley. Assuming the length of the key to be equal to the thickness of the pulley, the average shear stress developed in the key is given by
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4T ld -
16T ld² -
8T ld² -
16T πd3
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Correct Option: C
Force of the shaft circumference is given by
| P = | d/2 |
| ⇒ P = | d |
Shearing area = width × length
| = | × l = | 4 | 4 |
| Average shear stress = | Shearing area |
