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					 A particle of unit mass is moving on a plane. Its trajectory, in polar coordinates, is given by r(t) = t2, θ(t), where f is time. The kinetic energy of the particle at time t = 2 is
 
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Correct Option: C
r = t²
θ = t 
x = r cos θ = t² cost 
y = r sin θ = t² sint
| u = | = 2t cost - t² sint | dt | 
at t = 2
u = 4 cos 2 – 4 sin 2 = – 5.301
| v = | = 2t sin t + t² cos t | dt | 
at t = 2
v = 4 sin 2 + 4 cos 2 = 1.972
V = √u² + v² = 5.656
| K.E. = | = mv² | 2 | 
| = | = × 1 × 5.656² = 15.99 | 2 |