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Air of mass 1 kg. initially at 300 K and 10 bar, is allowed to expand isothermally till it reaches a pressure of 1 bar. Assuming air as an ideal gas with gas constant of 0.287 kJ/kg K, the change in entropy of air (in kJ/kg K, round off to two decimal places) is _________.
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- 0.66 kJ/kg K
- 1.66 kJ/kg K
- 0.33 kJ/kg K
- - 1.66 kJ/kg K
Correct Option: A
Air, m = 1 kg
P1 = 10 bar
R = 0.287 kJ/kg k Now,
∆s = S2 – S1
= mcpln | ![]() | T2 | ![]() | 0 - mRln | ![]() | P2 | ![]() | |||
T1 | P1 |
= - 1 × 0.287 ln | ![]() | 1 | ![]() | |||
10 |
= 0.66 kJ/kg k
∴ ∆s = 0.66 kJ/kg k