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Consider two fields
E = 120 π cos (106 πt – βx) ay V/m
and H = A cos (106 πt – βx) az A/m
The values of A and β which will satisfy the Maxwell's equation in a linear isotropic homogeneous lossless medium with εr = 8 and µr = 2 will be—A (in A/m) β (in rad/m) A. 1 0.0105 B. 1 0.042 C. 2 0.0105 D. 2 0.042
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- A
- B
- C
- D
Correct Option: D
We know that
| η = | √ | = | √ | ||
| ε | εrε0 |
| we get →H = | ⇒ | ||
| η | 120 π |
→H = cos (106πt − β X)az
→H = A cos (106πt − β X)
| A = | |
| η |
| = | ||
| √ | ||
| εrε0 |
| = | ||
| √ | (120π) | |
| ε0 |
| A = | √ | |
| μr |
| = | √ | = 2 | |
| 2 |
| for the lossless homogeneous medium phase velocity = | |
| β |
given, ω = 106 π
| v = | and v = | ||
| β | √μrεr |
| = | |
| √16 |
| ∴ β = | ⇒ | = 0.042 | ||
| 3 × 108 | 300 |
