Rectangular waveguide is designed to propagate the dominant

Rectangular waveguide is designed to propagate the dominant mode TE₁₀ at a frequency of 5 MHz. The cutoff frequency is 0.8 of signal frequency the raito of the waveguide height to width is 2 the dimension of the waveguide are—

We find the relation of waveguide that the cut-off frequency is given by relation

f_c =

√

m∏

n∏

2∏√με

for TE₁₀ mode m = 1 and n = 0 and b =	1
	a

f_c × 2∏	=	∏	⇒ a = 3.75 cm
c		a

and

b =	a	= 1.875 cm
	2