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An open wire transmission line has R = 5 Ω /m, L = 5.2 × 10– 8 H/n, G = 6.2 × 10– 3 S/m, C = 2.13 × 10–10 F/m. The signal frequency is 4 GHz. The impedance of the line for which there will be no reflection is in rectangular and polar form—
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- 179.44 + j 26.50, 181.39 ∠8.40º
- 15.623 + j 0.0205, 15.623 ∠– 0.075º
- 200 + j 26.50, 181.39 ∠8.40º
- 220 + j 26.50, 244 ∠– 0.75º
Correct Option: B
Evaluating the value by substituting in basic equation of characteristic impedance we get the impedance which is characteristic impedance
Z0 = | √ | = 15.623 ∠– 0.075 | |
G + jωC |