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A point charge Q is located on the surface of a sphere of radius R as shown in the figure. The average electric field on the surface of the sphere will be—
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- Infinite
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→ Q 1 (- n) 4πε0 R2 -
→ Q 1 (- n) 8πε0 R2 - Zero
Correct Option: C
The point charge Q elevates a total electric displacement flux of Q. If a plane is passed through the point of location of charge and tangential to the sphere, half the flux is on one side and half on the other. The first half of flux is passing through the spherical surface. Thus the average displacement density has a direction opposite to that of
| → |
| n |
and the magnitude is
| 4∏R2 |
so, average electric field is
| Eav = | –→ | where, | –→ | is the unit vector. | ||
| 8∏∈0R2 | (-n) | n |
