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In the figure shown below the force acting on the conductor PQ is in the direction of—
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- PQ
- QP
- –n
- n
Correct Option: C
The direction of flux density produced by all the elements of two veritcal sections of the current shown, at points on PQ is to the plane of the paper and outward. This can be checked with IB: Idl × IR. Then the force on an element of PQ is found from dF = Idl × B. Keeping in view the direction of dl which is the as that of l (at points on PQ, we find direction of force on PQ is along – n.)
