A 2 V peak to peak symmetrical wave is given to a rectifier

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A 2 V peak to peak symmetrical wave is given to a rectifier type ac voltmeter. The voltmeter will read:

1. 2·22 V
2. 1·11 V
3. 1 V
4. zero

Correct Option: B

For a square wave, the average or mean value always equal to the peak, value of the square wave. Here, given peak-to-peak value = 2V
so, peak value = 1V
We know that rectifier instrument read 1·1 times the average or mean value. Therefore, the voltmeter will read
1 × 1·11 = 1·11V