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The forward resistance of the diode shown below is 5 Ω and the remaining parameters are same as those of an ideal diode. The dc component of the source current is:
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Vm 50 π -
Vm 50√2π -
- Vm 100√2π -
2Vm 50 π
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Correct Option: A
Give that rf = 5 Ω, RL = 45 Ω
Here the diode acts as
a Half wave rectifier.
| Idc = | |
| π ( RL + rf ) |
| or Idc = | |
| π ( 45 + 5 ) |
| or Idc = | |
| 50 π |
