A CE amplifier with unbypassed emitter resistor RE has a

A CE amplifier with unbypassed emitter resistor R_E has a collector load R_C. Given R_C = 5 k ohms, R_E = 0.1 k ohms, h_fe = 99 and h_ie = 1 k ohm, the best estimate for | A_v| is given by:

A_V =	–h_fe · R_c
	h_ie + (1 + h_fe)2R_E

=	–99 × 5 × 10³
	1 × 10³ + (1 + 99)0·1 × 10³

=	–99 × 5	= – 45
	1 × 10

or | A_V | = | – 45 | = 45