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If the CMRR of the Op-amp is 60 dB, then magnitude of the output voltage is:
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- 1 mV
- 100 mV
- 200 mV
- 2 V
Correct Option: A
V– = | . 2 = 1 V | |
R + R |
V+ = | . 2 = 1 V | |
R + R |
Vd = V+ – V– = 0
given that
CMRR = 60 dB
60 = 20 log10 | ||||
ACM |
= 20 log10 Ad – 20 log10 Ac
60 = 0 – 20 log10 Ac
or 3 = – log10 Ac
or Ac = 10– 3 = 0.001
or Vo = ACM. | ||||
2 |
= 0.001 | ||||
2 |
= 0.001 = 1 mV