-
The 2-port network of fig. (1) has Y-parameter .The network is excited as shown in fig. (2). If IX = IY, the current I drawn from the source would be—
-
- V (Y11 + Y12 + Y21 + Y22)
- V (Y11 + Y22)
- V (Y11)
- V (Y11 + Y22 + Y12 – Y21)
Correct Option: A
From the figure (1)
I1 = V1 Y11 + V2 Y12 (i)
I2 = V1 Y21 + V2 Y22 (ii)
As from the figure (2) it is clear that terminal 2 and terminal 1 are at the same potential i.e.
V1 = V2 = V
and I = I1 + I2
or I = V (Y11 + Y12) + V (Y21 + Y22)
or I = V (Y11 + Y12 + Y21 + Y22)