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Calculate the value of current i—
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- 5 A
- 2 A
- 3 A
- 8 A
Correct Option: A
Current in branch BA, say i1
KCL at node B. i + i1 = 2
i1 = 1 amp.
Current in branch AC, say i2
KCL at node A:
6 = i1 + i2
6 = 1 + i2
i2 = 6 – 1 = 5 amp
Current in branch CD, say i3
KCL at node BC
4 + i2 = i3
4 + 5 = i3
or i3 = 9 amp current branch DE i.e. i
i + 8 = 9
i = 1A