Consider the circuit shown below—The voltage V1 and V2

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Consider the circuit shown below—

The voltage V₁ and V₂ are related as—

1. V₁ = 6i_a – 8 + V₂
2. V₁ = 6i_a + 8 + V₂
3. V₁ = – 6i_a + 8 + V₂
4. V₁ = – 6i_a – 8 + V₂

Correct Option: B

V₁ = 16 V
on applying KVL in loop

V₁ – 6 i_a – 8 – V₂ = 0
V₁ = V₂ + 8 + 6 i_a