Let i(t) = 3 te– 100 t A and V (t) = 0.6 (0.01

Home » Network Theory » Network Elements and the Concept of Circuit » Question

Let i(t) = 3 te^{– 100 t} A and V (t) = 0.6 (0.01 – t) e^{– 100 t} V for the network of fig. shown below. The power being absorbed by the network element at t = 5 ms is—

1. 18.4 µW
2. 9.2 µW
3. 16.6 µW
4. 8.3 µW

Correct Option: C

Power absorbed
P = V_i = 0.6 (0.01 – t) e^–100t .3.t.e^{– 100t}
Power at t = 5 ms = 5 × 10^{– 3}
P = 0.6 (0.01 – 5 × 10^{– 3}) e^{– 100 × 5 × 10^{– 3}} 3.5 × 10– 3 e^{– 100 × 5 × 10^{– 3}}
= 16.6 µW.
Hence alternative (C) is the correct choice.