-
For the 2-port as given below [Ya] = 
2 0 
mS 0 10 The value V0 is— Vs
-
-
3 3.2 -
1 16 -
2 33 -
1 17
-
Correct Option: A
| Given Ya = | ![]() | ![]() | mS. | |||
| 0 | 10 |
Its Z-parameter equivalent can be given as
| Z = | ||||||
| 2 × 10–3 | ||||||
| 0 | 10 × 10–3 |
| = | ![]() | ![]() | ||||
| 0 | 100 |
The equivalent Z-parameter at terminals AA′ and BB′
| Zeq = | ![]() | ![]() | + | ![]() | ![]() | ||||
| 0 | 100 | 100 | 100 |
| = | ![]() | ![]() | ||||
| 100 | 200 |
or V1 = 600 I1 + 100 I2 (A)
V2 = 100 I1 + 200 I2 (B)
VS = 60 I1 + V1 = 660 I1 + 100 I2 (C)
V2 = V0 = – 300 I2 (D)
and V2 = 100 I1 + 200 I2 (E)
from (D) and (E)
– 300 I2 = 100 I1 + 200 I2
or – 500 I2 = 100 I1
or – 5 I2 = I1

From equation (C)
VS = 660. (– 5 I2) + 100 I2
or VS = – 3300 + 100 I2 = – 3200 I2
| Now, | = | = | ||||
| Vs | –3200 | 32 |
Hence alternative (A) is the correct choice.