Voltage across the terminal a and b

Given circuit

KCL at node a (Assume potential at point b = 0V)

	V_a – V_b	+	V_a – 5	= 3
	2		2

or	V_a – 0	+	V_a – 5	= 3
	2		2

or V_a		1	+	1
		2		2

= 3 +	5
	2

or V_a = 5.5 V
Therefore V_ab = 5.5 V