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Network Elements and the Concept of Circuit

  1. Calculate Z parameter for the circuit given below—


    1. 14
      8
      1313
      216
      314
      117117
    2. 13
      13
      148
      117
      117
      216314
    3. 12
      9
      1313
      116
      114
      117117
    4. None of these
Correct Option: B

The given circuit can be redrawn as shown below

Applying KVL in loop 1.
V1 = 2 (I1 – I) ................(i)
KVL in loop 2
– 3I + 2V1 – (I2 + I) 4 + 2 (I1 – I) = 0
or 9I = 2V1 – 4 I2 + 2I1

or I =
2V1 + 2I1 – 4I2
...................(ii)
9

From equations (i) and (ii)
V1 = 2I1 – 2
(2V1 + 2I1 – 4I2)
9

or 9 V11 +
4
= 18I1 – 4I1 + 8I2
9

or 13V1 = 14 I1 + 8I2
or V1 =
14
I1 +
8
I2 ............(iii)
1313

We know that
V1 = Z11 I1 + Z12 I2 ..........(iv)
(for Z-parameter)
Comparing equations (iii) and (iv), we get
Z11 =
14
, Z12 =
8
1313

Applying KVL in loop 3.
V2 = 4 (I2 + I)
or V2 = 4 I2 + 4
2V1 + 2I1 – 4I2
9

[from equation (ii)]
or V2 = 4 I2 +
8
V1 +
8
I1
–16
I2
999

or V2 = 4 I2 +
8
14
I1 +
8
I2+
8
I1
–16
I2
9131399

or V2 = I24 +
64
16
+ I1
112
+
8
11791179

or V2 = I2
(466 + 64 – 208)
+ I1
112 + 104
117117

or V2 =
314
I2 +
216
I1 .......(v)
117117

We know that
V2 = Z21 I1 + Z22 I2 (for Z-parameters) ..............(vi)
Comparing equations (v) and (vi), we get
Z21 =
216
, Z22 =
314
117117

Hence alternative (A) is the correct choice.



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