In the circuit shown below, the voltage across 2Ω resistor

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In the circuit shown below, the voltage across 2Ω resistor is 20V. The 5Ω resistor connected between the terminals A and B can be replaced by an ideal—

1. Voltage source of 25 V with + terminal upward
2. Voltage source of 25 V with + terminal downward
3. Current source of 2 A upward
4. Current source of 2 A downward

Correct Option: A

Let the current I is flowing in 2Ω resistor

From figure

I_2Ω =	20	= 10A
	2

Current in branch AB: By applying current divison rule.

I_AB = I_2Ω ×	5	= 10 ×	5	= 5 A
	5 + 5		10

The voltage across terminal A and B = I_AB × R_AB
= 5 × 5 = 25 V
Thus 5Ω resistor connected between the terminals A and B can be replaced by an ideal voltage source of 25V with positive terminal upward.