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In the given circuit, if |I1| = |I2| = 10A—
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I1 will lead by tan–1 8 , I2 will lag by tan–1 8 6 6 -
I1 will lead by tan–1 6 , I2 will lag by tan–1 6 8 8 -
I1 will lead by tan–1 8 , I2 will lead by tan–1 8 6 6 -
I1 will lag by tan–1 6 , I2 will lead by tan–1 6 8 8
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Correct Option: C
The given circuit arrangement
Given |I1| = |I2| = 10 A. There will be no current in L so, remove L from circuit
Current in capacitor = 8JA
Current in resistence = 6A because |I1| = |I2| = 10 A
I1= 6 + J8 = 10 tan–1 | 6 |