For the network shown above, match List I (yparameter) with

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For the network shown above, match List I (yparameter) with List II (Value) and select the correct answer using the code given below the Lists:
List I (y-parameter) List II (Value)
A. Y₁₁ 1. s + 1
B. Y₁₂ 2. –1
C. Y₂₁ 3. 1 + 1/s
D. Y₂₂ 4. s

List I (y-parameter)	List II (Value)
A. Y₁₁	1. s + 1
B. Y₁₂	2. –1
C. Y₂₁	3. 1 + 1/s
D. Y₂₂	4. s

1. A B C D
  3 2 4 1
2. A B C D
  1 4 2 3
3. A B C D
  3 4 2 1
4. A B C D
  1 2 4 3

Correct Option: C

The given network.

From above figure
V₁ = (I₁ – I_a) s
or V₁ = I₁ s – I_a s ....(i)
Again V₁ = I_a 1 + V₂ ....(ii)
and V₁ = I_a 1 + (I₂ + I_a) 1/s

or V₁ =		1 +	1		I_a +	I₂	....(iii)
			s			s

From equation (ii)
I_a = V₁ – V₂
On putting the value of Ia in equation (i)
V₁ = I₁ s – (V₁ – V₂) s

or V₁ =		1 + s		V₂ s ....(iv)
		s

On comparing equation (iv) with standard equation
I₁ = V₁ Y₁₁ + V₂ Y₁₂, we get

Y₁₁ =	1 + s	; Y₁₂ = s
	s

and V₁=		1 +	1		V₁ – V₂ +	I₂
			s			s

I₂ = s		1 – 1 –	1		V₁ + V₂		1 +	1		s
			s					s

or I₂ = – V₁ + V₂ (s + 1) ....(v)
On comparing equation (v) with standard equation
I₂ = – V₁ Y₂₁ + V₂ Y₂₂, we get
Y₂₁ = – 1; Y₂₂ = s + 1
Hence alternative (C) is the correct choice.