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A parallel circuit has two branches. In one branch, R and L are in series and in the other branch, R and C are in series. The circuit will exhibit unity power factor when
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R = L C - R = LC
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R = C L -
R = L C
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Correct Option: A
We know that qualify factor Q is given by relation
Q = ωCR
| where ω = | |
| √LC |
At Q = 1
| 1 = ωCR = | CR | |
| √LC |
| or R = | √ | |
| C |
Hence alternative (A) is correct choice.
