For the circuit shown below, calculate Is (Given that current

For the circuit shown below, calculate I_s (Given that current in the galvanometer is zero)—

Given that current in the galvanometer is zero. It mean potential at point B and C is equal.
So, voltage at point
B = 5V
Current in branch

BD =	5V	= 1mA
	5K

Therefore voltage at terminal
A = 10K × 1mA + 5K × 1mA
= 15 V
Current in branch

AC =	V_A −V_C	=	15 − 5	= 2mA.
	5K		5K

Thus, I_s = 1 + 2 = 3 mA
Hence alternative (C) is the correct choice.