Home » Electrical Engineering materials » Electrical engineering material miscellaneous » Question

Electrical engineering material miscellaneous

Electrical Engineering materials

  1. The superconducting transition temperature of lead is 7.26K. If the initial field at 0 K is 64 × 103 amp/m, then the critical field at 5 K is:
    1. 0.3364 × 103 amp/m
    2. 0.364 × 103 amp/m
    3. 33.640 × 103 amp/m
    4. 336.400 × 103 amp/m
Correct Option: C

Field intensity at temperature T is given by relation

H (T) = H01 –
T2
TC2

where, H (T) = Field intensity at temperature T
TC = Critical temperature/transition temperature
H0 = Field intensity at zero degree kelvin
Given TC = 7·26° K
T=5° K
H0 = 64 × 103 amp/m
H (T) =?
Now, H (T) = 64 × 1031 –
5
2
7.26

= 33.64 × 103 amp/m



Your comments will be displayed only after manual approval.