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In the figure given, for the initial capacitor voltage is zero. The switch is closed at t = 0. The final steady-state voltage across the capacitor is—
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- 10V
- 5V
- 20V
- 0V
Correct Option: A
Capacitor will fully charge act an open.
I = | = 1Amp | 10 + 10 |
VC(0–) = 0 (given)
VC(∞) = Voltage across 10Ω terminal VC(∞) = 10 × 1
= 10V
