When a unit impulse voltage is applied to an inductor of

When a unit impulse voltage is applied to an inductor of 4 H, the energy supplied by the source is—

Current flow is given by
V (s)= LsI(s) – L i(0⁺)
I=LsI(s) {∵ initial conditions is not given}

or I(s) =		1	×	1	=	1	u(t) or I	=	1
		L		S		4			4

Low energy supplied =	1	LI²
	2

=		1	× 4 ×	1	=	1	J
		2		4²		8