The current I as marked in the figure is

Home » Network Theory » Network Elements and the Concept of Circuit » Question

The current I as marked in the figure is—

1. 3 A
2. 2 A
3. 1 A
4. 0 A

Correct Option: C

On applying superposition theorem.
Case I. Taken current source in this situation the 6A circuit becomes.

I =	6 × 1	2 (A → B)
	2 + 1

Case II. Taken voltage source: In this situation the circuit becomes I 1 O.C. 3V 1Ω 3Ω 4Ω A B 2Ω − + Note: Here 3 Ω resistance is a extra element because voltage at node B is independent of the resistance 3 Ω.

I₁ =	3	= 1 amp. (B → A)
	2 + 1

The net current in 2 Ω resistance
i = I – I₁ = 2 – 1 = 1 amp. (A → B)