The total impedance of the circuit shown is—

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The total impedance of the circuit shown is—

1. 20 Ω
2. (20 + J 10) Ω
3. (20 – J 10) Ω
4. (20 + J 5) Ω

Correct Option: A

Z_AB = (4 + j8) || (4 – j8) + 10

=	(4 + j8) (4 – j8)	+ 10
	4 + j8 + 4 – j8

=	16 + j32 – j32 – j² 64	+ 10
	8

=	16 + 64	+ 10 =	80	+ 10
	8		8

= 20 Ω