Correct Option: A

Complex power is given by the relation
P = I V
given V = 10 sin (2t – 40°)V
for the given circuit

10 sin (2t – 40°) volt

Z eq = 2 +		2 +	1		|| (1 + 5s)
			5s

= 3.02 ∠ 6.3° at ω = 2

I =		V	=	10 sin (2t – 40°)
		Zeq		3.02 – 6.3°

I = 3.3 sin (2t – 46.3°)
so, complex power

P = VI =	Vm Im	cos φ
	2

P =	10 × 3.3	∠ – 6.3°
	2

or P = 16.5 ∠ – 6.3° watts