Direction: Fig. shows the statement for given question.

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Current i at t = – 0.5 sec will be—
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50 amp 15 -
50 amp 20 - 5 amp
- 3 amp
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Correct Option: C
At t = – 0.5 sec
source 30 u (t + 1) → exist and equal to 30V.
2 u (1 – t) → exist and equal to 2 amp.
Now, we will draw the equivalent circuit under this situation, we get
By applying source transformation theorem, we get
Now apply KVL to the loop, we get
30 + 20 – 10 I = 0
I = | = 5 amp. | 10 |