-
The Laplace transform of the given function—
f (t) = t, t ≥ 4 sec 0, Otherwise will be—
-
-
e–4s s2 -
e–4(s + 1) s2 -
e–4s s -
e–4s t, t ≥ 4 sec 4s + 1 s2
-
Correct Option: D
Given f (t) = | ![]() | ![]() |
f (t) = t u (t – 4)
or f (t)= (t – 4 + 4) u (t – 4)
or f (t)= (t – 4) u (t – 4) + 4 u (t – 4)
or f (s) = | e– 4s + | e– 4s | s2 | 5 |

or f (s) = e– 4s | ![]() | 1 | + | 4 | ![]() |
s2 | s |
or f (s) = e– 4s | ![]() | 4s + 1 | ![]() | |
s2 |