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The Laplace transform of the given function—
f (t) = 
t, t ≥ 4 sec 0, Otherwise will be—
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e–4s s2 -
e–4(s + 1) s2 -
e–4s s -
e–4s 
t, t ≥ 4 sec 
4s + 1 s2
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Correct Option: D
| Given f (t) = | ![]() | ![]() |
f (t) = t u (t – 4)
or f (t)= (t – 4 + 4) u (t – 4)
or f (t)= (t – 4) u (t – 4) + 4 u (t – 4)
| or f (s) = | e– 4s + | e– 4s | s2 | 5 |

| or f (s) = e– 4s | ![]() | 1 | + | 4 | |
| s2 | s |
| or f (s) = e– 4s | ![]() | 4s + 1 | | |
| s2 |
