Correct Option: B

Method 1 (Direct approach) Compare the given circuit with the standard circuit. On comparing with standard equation


Z₁₁ = Z_a + Z_c = 5 + 8 = 13 Ω
Z₁₂ = Z₂₁ = Z_c = 8 Ω
Z₂₂ = Z_b + Z_c = 12 + 8 = 20 Ω
Method 2 (Alternative method)

V₁ = 5I₁ + 8 (I₁ + I₂)
or V₁ = 13I₁ + 8I₂ ....(i)
and V₂ = 12I₂ + 8 (I₁ + I₂)
or V₂ = 8I₁ + 20 I₂ ....(ii)
On comparing equation (i) and (ii) with the standard equation
V₁ = Z₁₁ I ₁ + Z₁₂ I₂
and V₂ = Z₂₁ I₁ + Z₂₂ I₂,
we get Z₁₁ = 13, Z₁₂ = 8 Ω, Z₂₁ = 8 Ω,
Z₂₂ = 20 Ω