The total power dissipated, the energy stored in the inductor

The total power dissipated, the energy stored in the inductor and the energy stored in the capacitor in the circuit shown in figure under steady state condition is—

The given circuit under the steady state looks like

i =	10	= 5A
	2

i_L (∞) = 2A

V_i (∞) = i_L (∞). 1 = 5 V
so, the power dissipated across the resistor
= i² (1 + 1) = 5² × 2 = 50 watt.
Energy stored in the inductor

=	1	Li²_L(∞) =	1	× 1.(5)² = 12.5 J
	2		2

Energy stored in the capacitor

=	1	C(V_x)² =	1	× 2 × 5² = 25 J
	2		2