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The inverse Laplace transform of 5(s + 3) — (s + 3)2 + 52
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- 5e– 3t
- 5 e– 3t cos 5t
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5 (s + 3)2 + 52 - 5 e– 5t
Correct Option: B
We know that
| L {cos t} = | |
| s2 + 12 |
| L {cos 5t) = | (by scaling property) | |
| s2 + 52 |
| L {e–3t cost 5t) = | (by using time shifting property) | |
| (s + 3)2 + 52 |
| so L {5 e–3t cost 5t) = | |
| (s + 3)2 + 52 |
