Photons of energy 1·53 × 10– 19 joule are incident on

Photons of energy 1·53 × 10^{– 19} joule are incident on a photodiode which has a respectivity of 0·65 A/W. If the optical power level is 10 µW, what is the photocurrent generated?

Responsivity, R = 0·65 A/ W
P₀ = Incident optical power
= 10 µW

Responsivity, R =	I_g
	P_o

or I_p = R·P₀
= 0·65 A/W × 10 µW = 6·5 µA
Hence alternative (D) is the correct choice.