In a transistor hfe = 50, hie = 830 Ω, hoe = 10

In a transistor h_fe = 50, h_ie = 830 Ω, h_oe = 10^{– 4^{. Its output resistance when used in CB configuration is about—}}

Given, h_fe = 50, h_ie = 830Ω, h_oe = 10^–4

For CB configuration, h_ob =	h_oe
	1 + h_fe

or h_ob =	10^–4
	1 + 50

Now, output resistance, R_ob =	1
	h_ob

=	51	= 510 kΩ
	10^–4

or Rob ≈ 500 kΩ
Hence alternative (B) is the correct choice.