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Consider the transistor circuit given below. It is desired to have V0 = Vin. What should be the value of R to achieve the condition. Assume VBE = 0·7 V, VCE(sat) = 0·2V and I = 8·6 mA—
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- 1 kΩ
- 500 Ω
- 2 kΩ
- 3 kΩ
Correct Option: B
The given circuit
Given, VBE = 0·7V, VCE(sat) = 0·2V and I = 8·6 mA The given circuit can be redrawn as
From above figure, applying KVL to the loop, we get
– IR – VBE + 5 = 0
or – (– 8·6 mA).R + 4·3 = 0
or R = | = 500 Ω | 8·6 mA |
Hence alternative (B) is the correct choice.