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In an Abrupt pn-junction the doping concentrations on the p-side and n-side are NA = 1017/cm3 and ND = 1016/cm3 respectively. It the pn-junction is reverse biased and total depletion width is 3 µm. The depletion width on p-side will be—
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- 0.3 µm
- 0.27 µm
- 2.7 µm
- None of these
Correct Option: B
Since the Net charge must be zero
NA WP = ND Wn
1017 × WP = 1016 × Wn
Wn = 10 WP …(i)
WP + Wn = 3 µm …(ii)
| from (i) and (ii) WP = | µm = 0.27 µm | 11 |
